2010 National Question 2 Single-choice Differentiating 2010_旧全国 II 卷 (2010·理) 2.(5分)函数 $y=\frac{1+\ln (x-1)}{2}(x>1)$ 的反函数是 A. $y=e^{2 x-1}-1 \quad(x>0)$B. $y=e^{2 x-1}+1 \quad(x>0)$C. $y=e^{2 x-1}-1 \quad(x \in R)$D. $y=e^{2 x-1+1} \quad(x \in R)$ Answer keyD ☆ SaveCan't do it, show the explanation查看原卷 →