2008 Sichuan Question 4 Single-choice Differentiating 2008_退役省自主命题 (2008·文) 4. (5分) (2008•四川)不等式|x﹣2|<1的解集为( ) A. {x|1<x<3}B. {x|0<x<2}C. {x|1<x<2}D. {x|2<x<3} Answer keyA ☆ SaveCan't do it, show the explanation查看原卷 →