2021 National Question 8 Single-choice Differentiating 2021_新课标II Paper 8.已知函数f(x)的定义域为R,f(x+2)为偶函数,f(2x+1)为奇函数,则() A. $f \left( - \frac { 1 } { 2 } \right) = 0$B. f(−$1) = 0$C. f(2)=0D. f(4)=0 Answer keyB ☆ SaveCan't do it, show the explanation查看原卷 →