2009 Guangdong Question 16 Single-choice Differentiating 2009_退役省自主命题 (2009·文) 8.(5分)(2009•广东)函数f(x)=(x﹣3)ex的单调递增区间是( ) A. (﹣∞,2)B. (0,3)C. (1,4)D. (2,+∞) Answer keyD ☆ SaveCan't do it, show the explanation查看原卷 →