1.(2013广东,文1)设集合 $S=\left\{x \mid x^{2}+2 x=0, x \in \mathbf{R}\right\}, ~ T=\left\{x \mid x^{2}-2 x=0, x \in \mathbf{R}\right\}$ ,则 $S \cap T=$ .
参考答案A
2013_退役省自主命题 (2013·文)
1.(2013广东,文1)设集合 $S=\left\{x \mid x^{2}+2 x=0, x \in \mathbf{R}\right\}, ~ T=\left\{x \mid x^{2}-2 x=0, x \in \mathbf{R}\right\}$ ,则 $S \cap T=$ .
【解答】
答案:A
解析:$\because S=\{-2,0\}, ~ T=\{0,2\}, ~ \therefore S \cap T=\{0\}$ .
2 .
答案:C
解析:要使函数有意义,则 $\left\{\begin{array}{l}x+1>0, \\ x-1 \neq 0,\end{array}\right.$
解得 $x>-1$ 且 $x \neq 1$ ,
故函数的定义域为 $(-1,1) \cup(1,+\infty)$ .
3 .
答案:D
解析:$\because \mathrm{i}(x+y \mathrm{i})=-y+x \mathrm{i}=3+4 \mathrm{i}$ ,
$\therefore\left\{\begin{array}{l}x=4, \\ y=-3 .\end{array}\right.$
$\therefore x+y \mathrm{i}=4-3 \mathrm{i}$ .
$\therefore|x+y \mathrm{i}|=\sqrt{4^{2}+(-3)^{2}}=5$ .